return value of strtod() if string equals to zero

Question

As per MSDN:

• strtod returns 0 if no conversion can be performed or an underflow occurs.

What if my string equals to zero (i.e., 0.0000)

Answer 1

The signature is (give or take restrict keywords):

 double strtod(const char *nptr, char **endptr);

If you pass a non-null pointer as the second argument, it will be returned with the value of nptr if it could perform no conversion. If it found a genuine zero in the input string, then the value stored in *endptr won't be nptr.

char *end;
const char *data = "0.00000";

errno = 0;
double d = strtod(data, &end);
if (end != data)
    ...a conversion was performed...
else
    ...trouble...

You can also look at errno, but you need to zero it before the call because no function in the standard C library or the POSIX library sets errno to zero.

The standard says:

If the subject sequence is empty or does not have the expected form, no conversion is performed; the value of nptr is stored in the object pointed to by endptr, provided that endptr is not a null pointer.

Returns

The functions return the converted value, if any. If no conversion could be performed, zero is returned. If the correct value overflows and default rounding is in effect (7.12.1), plus or minus HUGE_VAL, HUGE_VALF, or HUGE_VALL is returned (according to the return type and sign of the value), and the value of the macro ERANGE is stored in errno. If the result underflows (7.12.1), the functions return a value whose magnitude is no greater than the smallest normalized positive number in the return type; whether errno acquires the value ERANGE is implementation-defined.