C/C++ - executable path

Question

I want to get the current executable\'s file path without the executable name at the end.

I\'m using:

char path[1024];
uint32_t size = sizeof(path);
if (         


        

Answer 1

For Linux:
Function to execute system command

int syscommand(string aCommand, string & result) {
    FILE * f;
    if ( !(f = popen( aCommand.c_str(), "r" )) ) {
            cout << "Can not open file" << endl;
            return NEGATIVE_ANSWER;
        }
        const int BUFSIZE = 4096;
        char buf[ BUFSIZE ];
        if (fgets(buf,BUFSIZE,f)!=NULL) {
            result = buf;
        }
        pclose( f );
        return POSITIVE_ANSWER;
    }

Then we get app name

string getBundleName () {
    pid_t procpid = getpid();
    stringstream toCom;
    toCom << "cat /proc/" << procpid << "/comm";
    string fRes="";
    syscommand(toCom.str(),fRes);
    size_t last_pos = fRes.find_last_not_of(" \n\r\t") + 1;
    if (last_pos != string::npos) {
        fRes.erase(last_pos);
    }
    return fRes;
}

Then we extract application path

    string getBundlePath () {
    pid_t procpid = getpid();
    string appName = getBundleName();
    stringstream command;
    command <<  "readlink /proc/" << procpid << "/exe | sed \"s/\\(\\/" << appName << "\\)$//\"";
    string fRes;
    syscommand(command.str(),fRes);
    return fRes;
    }

Do not forget to trim the line after