Logically determine game outcome with formula

Question

I am trying to become a better coder, which includes getting rid of my \'hard-coding\' habits to keep my programs dynamic and easy to maintain.

Right now I am writing a

Answer 1

This is really cool! So, I think I would use a dictionary to control what loses to what:

dict_loss = dict()
dict_loss['paper']='scissors'
dict_loss['scissors']='rock'
dict_loss['rock']='paper'

Then the players make a choice and you just check if their choices fall into the dictionaries:

player_1='paper'
player_2='rock'

if player_2 in dict_loss[player_1]:
    print("Player 2 Wins")
else:
    if player_1 in dict_loss[player_2]:
        print("Player 1 Wins")
    else:
        print("DRAW")

You can extend the dictionary with the new objects you get, I'm not sure how Pans, swords and riffles work, but you can do:

dict_loss['paper']=['scissors', 'riffle']

if paper loses to riffles, and so on...

Hope this helps, if you have any "data structure" restrictions let me know and I will try to think of something different.