Why Segmentation fault in following code?

Question

I read this on wikipedia

    int main(void)
 {

    char *s = \"hello world\";
    *s = \'H\';

 }

When the program containing this code is com

Answer 1

first have a good understanding of pointers, I will give u a short demo:

First let us analyze your code line by line. Lets start from main onwards

char *s = "Some_string";

first of all, you are declaring a pointer to a char variable, now *s is a address in memory, and C will kick you if you try to change its memory value, thats illegal, so u better declare a character array, then assign s to its address, then change s.

Hope you get, it. For further reference and detailed understanding, refer KN King: C programming A Modern Approach