Why Segmentation fault in following code?

Question

I read this on wikipedia

    int main(void)
 {

    char *s = \"hello world\";
    *s = \'H\';

 }

When the program containing this code is com

Answer 1

There is a big difference between:

char * s = "Hello world";

and

char s[] = "Hello world";

In the first case, s is a pointer to something that you can't change. It's stored in read-only memory (typically, in the code section of your application).

In the latter case, you allocate an array in read-write memory (typically plain RAM), that you can modify.