Enumerate list of elements starting from the second element

Question

I have this list

[[\'a\', \'a\', \'a\', \'a\'],
 [\'b\', \'b\', \'b\', \'b\', \'b\'],
 [\'c\', \'c\', \'c\', \'c\', \'c\']]

and I want to conca

Answer 1

There is not much merit here for using enumerate() ... you can simply .pop() the n-th item from inner lists. For loop over your data, starting at index 1 and add the 2nd value (popped) to the 1st element of the inner list:

data = [['a', 'a', 'a', 'a'],
 ['b', 'b', 'b', 'b', 'b'],
 ['c', 'c', 'c', 'c', 'c']] 

for row in range(1,len(data)):  # apply to 1st to n-th inner list by index
    item = data[row].pop(2)         # remove the 2nd item from inner list
    data[row][1] += item            # add it to the 1st of inner list

print(data)

Output:

[['a', 'a', 'a', 'a'], 
 ['b', 'bb', 'b', 'b'], 
 ['c', 'cc', 'c', 'c']]

See list.pop(index)