Say for example I\'m trying to convert an object with 10 fields to Json, however I need to modify the process of serializing 1 of these fields. At the moment, I\'d have to use m
You can try by decorating the property you need to modify manually with JsonConverterAttribute
and pass the appropriate JsonConverter
type.
For example, using OP's original example:
public class IntegerConverter : JsonConverter
{
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
serializer.Serialize(writer, Convert.ToInt32(value));
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
public override bool CanConvert(Type objectType)
{
return objectType == typeof(string);
}
}
class TestJson
{
public string Field1 { get; set; }
public string Field2 { get; set; }
public string Field3 { get; set; }
[JsonConverter(typeof(IntegerConverter))]
public string Field4 { get; set; }
}
You can then serialize the object as usual using JsonConvert
:
var test = new TestJson {Field1 = "1", Field2 = "2", Field3 = "3", Field4 = "4"};
var jsonString = JsonConvert.SerializeObject(test);