Dev-C++ Input skipped

Question

#include
#include
main()
{
      int i;
      char c, text[30];
      float f;
      printf(\"\\nEnter Integer : \");
      scanf(\"%d\",&a         


        

Answer 1

Scanf or other input parsing functions take only required quantity of characters as specified in the call from stdin and reject others.As a result these rejected values,during next read of stdin enter into the variables along with the newline characters and thus skipping inputs for a few calls.So its better to call a clear routine that cleans stdin and stops garbage entering into other variables.

Although your code is quite vulnerable still it has solution:-

#include

  int clear()
  {
    while ((getchar())^'\n');    
  }
  int  main()
    {
          int i;
          char c, text[30]={0};
          float f;
          printf("\nEnter Integer : ");
          scanf(" %d",&i);
          printf("\nEnter Character : ");     
          scanf(" %c",&c);    
          printf("\nEnter String:");
      clear();
          gets(text);
          printf("\nEnter Float:");   
          scanf(" %f",&f);    
          printf("\nInteger : %d",i);
          printf("\nCharacter : %c",c);
          printf("\nString : %s",text);
          printf("\nFloat : %f",f);
          getchar();
    }