std::move() is just casting?

Question

I have read a few (pesudo) implementions of std::move(). And all are just casting away the reference of the parameter and then returning it as a rvalue reference.

It do

Answer 1

Yes, std::move is a bit of a misnomer as it doesn't actually move anything. It is used to indicate that an object may be "moved from".

It does this by casting the object to a T&&. cppreference states the return value is static_cast::type&&>(t). (btw, that is exactly what VS2017 does)

I don't know precisely what the standard says on the matter.