Consider example:
def func_b(a):
print a
def func_a():
a = [-1]
for i in xrange(0, 2):
a[0] = i
func_b(a)
And test
The following works (the importing mock
from unittest
is a Python 3 thing, and module
is where func_a
and func_b
are):
import mock
from mock import call
import copy
class ModifiedMagicMock(mock.MagicMock):
def _mock_call(_mock_self, *args, **kwargs):
return super(ModifiedMagicMock, _mock_self)._mock_call(*copy.deepcopy(args), **copy.deepcopy(kwargs))
This inherits from MagicMock
, and redefines the call behaviour to deepcopy the arguments and keyword arguments.
def test_a():
from module import func_a
with mock.patch('module.func_b', new_callable=ModifiedMagicMock) as func_b_mock:
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])
You can pass the new class into patch
using the new_callable
parameter, however it cannot co-exist with autospec
. Note that your function calls func_b
with a list, so call(0), call(1)
has to be changed to call([0]), call([1])
. When run by calling test_a
, this does nothing (passes).
Now we cannot use both new_callable
and autospec
because new_callable
is a generic factory but in our case is just a MagicMock
override. But Autospeccing is a very cool mock
's feature, we don't want lose it.
What we need is replace MagicMock
by ModifiedMagicMock
just for our test: we want avoid to change MagicMock
behavior for all tests... could be dangerous. We already have a tool to do it and it is patch
, used with the new
argument to replace the destination.
In this case we use decorators to avoid too much indentation and make it more readable:
@mock.patch('module.func_b', autospec=True)
@mock.patch("mock.MagicMock", new=ModifiedMagicMock)
def test_a(func_b_mock):
from module import func_a
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])
Or:
@mock.patch("mock.MagicMock", new=ModifiedMagicMock)
def test_a():
with mock.patch('module.func_b') as func_b_mock:
from module import func_a
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])