How to set a function as function argument in Swift 3

Question

Q: Is it possible to pass a function as function argument in Swift 3?

To refactor my code, I want to have a global function. At the end of this function

Answer 1

Yes you can pass a function/closure as parameter of another function.

This is the syntax

func doSomething(closure: () -> ()) {
    closure()
}

here the function doSomething receives as parameter a closure with no params and no return type.

You can call doSomething with this syntax

doSomething(closure: { _ in print("Hello world") })

Or using the trailing closure syntax

doSomething { 
    print("Hello world")
}