I can do what the following code shows:
std::string a = \"chicken \";
std::string b = \"nuggets\";
std::string c = a + b;
However, this fails:<
Both "chicken"
and "nuggets"
has type const char*
(as literals in code). So you are trying to add to pointers.
Try
std::string c = std::string("chicken") + "nuggets";
std::string is not part of language itself, it's a part of standard library. C++ aims to have as few language features as possible. So built-in type for strings is not present in parser etc. That's why string literals will be treaded as pointers.
EDIT
To be completely correct: type of literals is really const char[N]
(where N is character count in literal +1 for \0
. But in C++ arrays ([]
) can be treated as pointers, and that is what compiler tries to do (as it cannot add arrays)