In C#, the interface can be instantiated?

Question

I\'m reading the code in here. I find that private ITreeModel _model; in TreeList.cs:

namespace Aga.Controls.Tree
{
    public class TreeList: L         


        

Answer 1

_model is a member of TreeList and that means that you can create an instance of a class and then it will contain an instance of some class. for example

_model = new TreeModel(); 

will make _model contain an instance

but you cannot do

_model = new ITreeModel(); 

because ITreeModel is and interface and you cannot create an instance of an interface