Why does 2 dimension array passing to function requires its size?

Question

Inspired this quiestion .

Why does -

void display(int p[][SIZE]) // allowed

and

void display(int p[][]) // not a         


        

Answer 1

That's because caculations in pointers requires that. When p points to 2 dimentional array that's size is SIZE this operation p+=3 is calculated this way:

if the value of p is a constant equal ADRESS p receive this value ADRESS + 3*SIZE.

That's because arithmitic in pointers is different from arithmitic in real numbers. This calculation can't be done without knowing the size of the array.