Query using “CASE WHEN” statement in WHERE causes QuerySyntaxException: unexpected AST

Question

I\'m trying to make a query using Spring Data, but I cannot make it work:

@Query(SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0)          


        

Answer 1

It looks like Hibernate cannot evaluate the result of a CASE expression when it returns a boolean literal directly. A workaround is to make the CASE expression part of another expression, e.g. by comparing it to another boolean literal.

So instead of:

... AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END

Try:

... AND (CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END) = TRUE

But looking at that expression, wouldn't it be simpler to just do:

... AND (:minVal <= 0 OR val <= :minVal)

Is it not equivalent?