Find the index of the second occurrence of a string inside a list

Question

This is my list and code:

x=[[\"hi hello\"], [\"this is other\"],[\"this\"],[\"something\"],[\"this\"],[\"last element\"]]
for line in x:
    y=x.index(line)         


        

Answer 1

If getting the indices of the keyword is the only thing you need to do, then storing strings in a list is unnecessary (even if this was just an example you thought of!).

This function would print out each line and all the indices of the keyword (if any) that you give found per line in the file:

def getIndices(keyword):

    f = open('pathToYourFile', 'r')
    for line in f:

        wordList = line.split()
        buf = line.strip("\n") + ": "

        i = 0
        while i < len(wordList):
            if wordList[i] == keyword:
                buf += str(i) + " "
            i += 1

        print buf

This way you won't be limited to the keyword "this" and 1st/2nd occurrences. For example, let's say your file looked like this:

hello this
this is cool
hello there
this this this

Then the function will work like this:

>>> getIndices("this")
hello this: 1 
this is cool: 0 
hello there: 
this this this: 0 1 2