move semantics std::move how use it

Question

#include 

template
typename std::remove_reference::type&& move(T&& v)
{
    return v;
}

void main()
{
           


        

Answer 1

This is straight out of the C++0x draft standard (§20.2.3/6):

template typename remove_reference::type&& move(T&& t) noexcept;

Returns: static_cast::type&&>(t).

Consequently, if you change your move implementation to the following, it works just fine:

template
typename std::remove_reference::type&& move(T&& v)
{
    return static_cast::type&&>(v);
}