I am following Learning Rust With Entirely Too Many Linked Lists to write my first program in Rust. I changed the program to:
use std::mem;
Whenever you write recursive (or iterative) code, you need to have a stopping condition. Your code doesn't, so it loops forever.
Producing a MCVE of your problem is always a good start:
use std::mem;
#[derive(Debug)]
pub enum List {
Nil,
More(Box),
}
impl Drop for List {
fn drop(&mut self) {
let mut head = mem::replace(self, List::Nil);
while let List::More(ref mut node) = mem::replace(&mut head, List::Nil) {
head = mem::replace(node, List::Nil);
}
}
}
#[test]
fn basics() {
List::Nil;
}
Then annotate the code to see where it's recurring:
fn drop(&mut self) {
eprintln!("1");
let mut head = mem::replace(self, List::Nil);
eprintln!("2");
while let List::More(ref mut node) = mem::replace(&mut head, List::Nil) {
eprintln!("3");
head = mem::replace(node, List::Nil);
eprintln!("4");
}
eprintln!("5");
}
This prints out
1
2
1
2
so delete everything after that:
fn drop(&mut self) {
eprintln!("1");
let mut head = mem::replace(self, List::Nil);
eprintln!("2");
}
Why does this cause infinite recursion? You've defined it so that in order to drop List
, you have to create a new List
, which in turn needs to be dropped, which creates a new List
, which...
Add a stopping condition:
fn drop(&mut self) {
if let List::Nil = *self { return }
let mut head = mem::replace(self, List::Nil);
while let List::More(ref mut node) = mem::replace(&mut head, List::Nil) {
head = mem::replace(node, List::Nil);
}
}
No more infinite recursion.
Then expand back out to the original and try again. It works for this test case, but not for List::More(Box::new(List::Nil))
so we shrink it back:
fn drop(&mut self) {
eprintln!("1");
if let List::Nil = *self { return }
eprintln!("2");
let mut head = mem::replace(&mut *self, List::Nil);
eprintln!("3");
while let List::More(ref mut node) = mem::replace(&mut head, List::Nil) {
eprintln!("4");
head = mem::replace(node, List::Nil);
eprintln!("5");
}
eprintln!("6");
}
1
2
3
4
1
5
1
2
3
4
1
5
The problem now is that when we re-assign head
, the value we are overwriting needs to be dropped, which triggers the recursion again.
Fixing this is complicated. Like, surprisingly so. You ready for this?
impl Drop for List {
fn drop(&mut self) {
match *self {
List::Nil => return,
List::More(ref more) => {
if let List::Nil = **more {
return;
}
}
}
let mut head = mem::replace(self, List::Nil);
while let List::More(ref mut next) = {head} {
head = mem::replace(next, List::Nil);
}
}
}
This now has two stopping conditions:
Nil
More(Nil)
In every other case, we iteratively convert the More(x)
into a More(Nil)
, which is handled by the stopping condition. That means that we only have a single depth of recursion: for each value that is dropped when the previous value of head
goes out of scope when it is replaced.
For your original code:
impl Drop for List {
fn drop(&mut self) {
match *self {
List::Nil => return,
List::More(ref more) => {
if let List::Nil = more.next {
return;
}
}
}
let mut head = mem::replace(self, List::Nil);
while let List::More(ref mut node) = {head} {
head = mem::replace(&mut node.next, List::Nil);
}
}
}
In the original tutorial you linked, this isn't a problem because the definition of List::drop
doesn't modify self
at all so it's not self-recursive:
impl Drop for List {
fn drop(&mut self) {
let mut cur_link = mem::replace(&mut self.head, Link::Empty);
while let Link::More(mut boxed_node) = cur_link {
cur_link = mem::replace(&mut boxed_node.next, Link::Empty);
}
}
}