sort 2 array with the values of one of them in javascript

Question

i have two array, lets say priceArray= [1,5,3,7]

userIdArray=[11, 52, 41, 5]

i need to sort the priceArray, so that the userIdArray will be also sorted. for

Answer 1

Taken from Sorting with map and adapted for the userIdArray:

// the array to be sorted
var priceArray = [1, 5, 3, 7],
    userIdArray = [11, 52, 41, 5];

// temporary array holds objects with position and sort-value
var mapped = priceArray.map(function (el, i) {
    return { index: i, value: el };
});

// sorting the mapped array containing the reduced values
mapped.sort(function (a, b) {
    return a.value - b.value;
});

// container for the resulting order
var resultPrice = mapped.map(function (el) {
    return priceArray[el.index];
});
var resultUser = mapped.map(function (el) {
    return userIdArray[el.index];
});

document.write('
' + JSON.stringify(resultPrice, 0, 4) + '
');
document.write('
' + JSON.stringify(resultUser, 0, 4) + '
');

With proper data structure, as rrowland suggest, you might use this:

var data = [{
        userId: 11, price: 1
    }, {
        userId: 52, price: 15
    }, {
        userId: 41, price: 13
    }, {
        userId: 5, price: 17
    }];

data.sort(function (a, b) {
    return a.price - b.price;
});

document.write('
' + JSON.stringify(data, 0, 4) + '
');

A bit shorter with ES6

var priceArray = [1, 5, 3, 7],
    userIdArray = [11, 52, 41, 5],
    temp = Array.from(priceArray.keys()).sort((a, b) => priceArray[a] - priceArray[b]);

priceArray = temp.map(i => priceArray[i]);
userIdArray = temp.map(i => userIdArray[i]);

console.log(priceArray);
console.log(userIdArray);

.as-console-wrapper { max-height: 100% !important; top: 0; }