Define new function, array, struct etc inside of parameter of function call [duplicate]

Answer 1

You must be just another victim of the people that start with java and then trying to get into c, that's why I will answer.

I want to initialize my array inside of that parameter. How can that be done?

You cannot. _{prior to C99}

---

In general, this is something you could do:

#include 

void foo(char** arr, int size)
{
    int i;
    for(i = 0; i < size; ++i)
        printf("%s\n", arr[i]);
}

void bar(char** arr)
{
    while(*arr)
        printf("%s\n", *arr++);
}

int main(void)
{
    char* x[] = { "hello", "my", "friend" };
    foo(x, 3);

    char* null_terminated[] = { "ShadowRanger", "Correct", NULL };
    bar(null_terminated);

    return 0;
}

where foo() uses the size of the array explicitly, while bar() requires the array to be NULL terminated.