google maps circle to polyline coordinate array

前端 未结 1 1683
走了就别回头了
走了就别回头了 2021-01-20 10:59

how to get array of polyline coordinates from google.maps.Circle\'s object

\"enter

1条回答
  •  隐瞒了意图╮
    2021-01-20 11:13

    A google.maps.Circle doesn't contain an array of coordinates. If you want a google.maps.Polygon that is shaped like a circle, you need to make one.

    function drawCircle(point, radius, dir) { 
      var d2r = Math.PI / 180;   // degrees to radians 
      var r2d = 180 / Math.PI;   // radians to degrees 
      var earthsradius = 3963; // 3963 is the radius of the earth in miles
    
      var points = 32; 
    
      // find the raidus in lat/lon 
      var rlat = (radius / earthsradius) * r2d; 
      var rlng = rlat / Math.cos(point.lat() * d2r); 
    
      var extp = new Array(); 
      if (dir==1) {
         var start=0;
         var end=points+1; // one extra here makes sure we connect the path
      } else {
         var start=points+1;
         var end=0;
      }
      for (var i=start; (dir==1 ? i < end : i > end); i=i+dir)  
      { 
         var theta = Math.PI * (i / (points/2)); 
         ey = point.lng() + (rlng * Math.cos(theta)); // center a + radius x * cos(theta) 
         ex = point.lat() + (rlat * Math.sin(theta)); // center b + radius y * sin(theta) 
         extp.push(new google.maps.LatLng(ex, ey)); 
      } 
      return extp;
    }
    
    var circle = new google.maps.Polygon({
                   map: map,
                   paths: [drawCircle(new google.maps.LatLng(-33.9,151.2), 100, 1)],
                   strokeColor: "#0000FF",
                   strokeOpacity: 0.8,
                   strokeWeight: 2,
                   fillColor: "#FF0000",
                   fillOpacity: 0.35
    });
    

    Example

    code snippet:

    function drawCircle(point, radius, dir) {
      var d2r = Math.PI / 180; // degrees to radians 
      var r2d = 180 / Math.PI; // radians to degrees 
      var earthsradius = 3963; // 3963 is the radius of the earth in miles
    
      var points = 32;
    
      // find the raidus in lat/lon 
      var rlat = (radius / earthsradius) * r2d;
      var rlng = rlat / Math.cos(point.lat() * d2r);
    
    
      var extp = new Array();
      if (dir == 1) {
        var start = 0;
        var end = points + 1
      } // one extra here makes sure we connect the
      else {
        var start = points + 1;
        var end = 0
      }
      for (var i = start;
        (dir == 1 ? i < end : i > end); i = i + dir) {
        var theta = Math.PI * (i / (points / 2));
        ey = point.lng() + (rlng * Math.cos(theta)); // center a + radius x * cos(theta) 
        ex = point.lat() + (rlat * Math.sin(theta)); // center b + radius y * sin(theta) 
        extp.push(new google.maps.LatLng(ex, ey));
        bounds.extend(extp[extp.length - 1]);
      }
      // alert(extp.length);
      return extp;
    }
    
    var map = null;
    var bounds = null;
    
    function initialize() {
      var myOptions = {
        zoom: 10,
        center: new google.maps.LatLng(-33.9, 151.2),
        mapTypeControl: true,
        mapTypeControlOptions: {
          style: google.maps.MapTypeControlStyle.DROPDOWN_MENU
        },
        navigationControl: true,
        mapTypeId: google.maps.MapTypeId.ROADMAP
      }
      map = new google.maps.Map(document.getElementById("map_canvas"),
        myOptions);
    
      bounds = new google.maps.LatLngBounds();
    
      var donut = new google.maps.Polygon({
        paths: [drawCircle(new google.maps.LatLng(-33.9, 151.2), 100, 1),
          drawCircle(new google.maps.LatLng(-33.9, 151.2), 50, -1)
        ],
        strokeColor: "#0000FF",
        strokeOpacity: 0.8,
        strokeWeight: 2,
        fillColor: "#FF0000",
        fillOpacity: 0.35
      });
      donut.setMap(map);
    
      map.fitBounds(bounds);
    }
    google.maps.event.addDomListener(window, 'load', initialize);
    html,
    body,
    #map_canvas {
      width: 100%;
      height: 100%;
      padding: 0px;
      margin: 0px;
    }
    
    

    0 讨论(0)
提交回复
热议问题