How can I get a table of dates from the first day of the month, two months ago, to yesterday?

Question

I have a situation that I would normally solve by creating a feeder table (for example, every date between five years ago and a hundred years into the future) for querying b

Answer 1

This just does sequential days between two dates, but I've posted to show you can eliminate the recursive error by supplying a limit.

with temp (level, seqdate) as 
(select 1, date('2008-01-01')
from sysibm.sysdummy1
union all
select level, seqdate + level days
from temp
where level < 1000 
and seqdate + 1 days < Date('2008-02-01')
)
select seqdate as CalendarDay
from temp
order by seqdate

---

Update from pax:

This answer actually put me on the right track. You can get rid of the warning by introducing a variable that's limited by a constant. The query above didn't have it quite right (and got the dates wrong, which I'll forgive) but, since it pointed me to the problem solution, it wins the prize.

The code below was the final working version (sans warning):

WITH DATERANGE(LEVEL,DT) AS (
  SELECT 1, CURRENT DATE + (1 - DAY(CURRENT DATE)) DAYS - 2 MONTHS
    FROM SYSIBM.SYSDUMMY1
  UNION ALL SELECT LEVEL + 1, DT + 1 DAY
    FROM DATERANGE
    WHERE LEVEL < 1000 AND DT < CURRENT DATE - 1 DAY
) SELECT DT FROM DATERANGE;

which outputs, when run on the 2^nd of February:

----------
    DT
----------
2009-12-01
2009-12-02
2009-12-03
:  :  :  :
2010-01-30
2010-01-31
2010-02-01

DSNE610I NUMBER OF ROWS DISPLAYED IS 63
DSNE616I STATEMENT EXECUTION WAS SUCCESSFUL.