SED: addressing two lines before match

Question

Print line, which is situated 2 lines before the match(pattern).

I tried next:

sed -n \': loop
/.*/h
:x
{n;n;/cen/p;}
s/./c/p
t x
s/n/c/p
t loop
{g;p         


        

Answer 1

If you can use awk try this:

awk  '/pattern/ {print b} {b=a;a=$0}' file

This will print two line before pattern