Process.Start filename using %temp%

Question

For some odd reaseon this code fails:

p.StartInfo.FileName = @\"%temp%\\SSCERuntime_x86-ENU.msi\";

and this code succes:

p.         


        

Answer 1

Try this:

string tempPath = Environment.GetEnvironmentVariable("Temp");

Then concat it in:

p.StartInfo.FileName = Path.Combine(tempPath, "SSCERuntime_x86-ENU.msi"); 

Casper beat me to the punch on the explaination, but the Process.Start method basically treats it literally instead of intrperting it as the shell would.