Process.Start filename using %temp%

Question

For some odd reaseon this code fails:

p.StartInfo.FileName = @\"%temp%\\SSCERuntime_x86-ENU.msi\";

and this code succes:

p.         


        

Answer 1

%TEMP% is parsed and evaluated by Command Shell. You could use use Path.GetTempPath() and Path.Combine for this purpose.

p.StartInfo.FileName = Path.Combine(Path.GetTempPath(), @"SSCERuntime_x86-ENU.msi");