Partially specializing member-function implementations

Question

I\'m currently refactoring some code the explicitly specializes a member function of a class template with two template parameters.

template 

        

Answer 1

You can achieve that by using a specialize functor instead a function :

#include 

typedef int SomeType;

template 
class BarFunctor {
public:
    void operator()() {
        std::cout << "generic" << std::endl;
    }
};

template <>
class BarFunctor {
public:
    void operator()() {
        std::cout << "special" << std::endl;
    }
};

template 
class Foo {
public:
    void helloWorld() {
        std::cout << "hello world !" << std::endl;
    }

    void bar() {
        return _bar();
    }

private:
    BarFunctor _bar;
};

int main() {

    Foo gen;
    Foo spe;
    gen.helloWorld();
    spe.helloWorld();
    gen.bar();
    spe.bar();
    return 0;
}