Search through a 2-dimensional list without numpy

Question

I\'m looking to define a function that accepts two parameters: an int and a list.

If the function finds the integer in the list it returns

Answer 1

You can do something like this:

l = [
         [0, 0, 0, 0, 0, 0, 0, 0, 0],
         [0, 2, 1, 1, 0, 1, 1, 1, 0],
         [0, 1, 0, 1, 0, 0, 0, 1, 0],
         [0, 1, 0, 1, 1, 1, 0, 1, 0],
         [0, 1, 0, 0, 0, 1, 0, 1, 0],
         [0, 1, 1, 1, 0, 1, 0, 1, 0],
         [0, 0, 0, 1, 0, 1, 0, 1, 0],
         [0, 1, 1, 1, 0, 1, 0, 1, 0],
         [0, 1, 0, 0, 0, 0, 0, 1, 0],
         [0, 1, 0, 1, 1, 1, 0, 1, 0],
         [0, 1, 0, 1, 0, 1, 0, 1, 0],
         [0, 1, 1, 1, 0, 1, 1, 4, 0],
         [0, 0, 0, 0, 0, 0, 0, 0, 0]
    ]

def findElement(element, l):
    for i in range(len(l)):
        for j in range(len(l[i])):
            if element==l[i][j]:
                return (i,j)
    return None

print(findElement(4,l))

Output:

(11, 7)