Sum of all rows of all columns - Bash

Question

I have a file like this

1 4 7 ...
2 5 8
3 6 9 

And I would like to have as output

6 15 24 ...

That is the

Answer 1

AWK Program

#!/usr/bin/awk -f

{
    print($0);
    len=split($0,a);
    if (maxlen < len) {
        maxlen=len;
    }
    for (i=1;i<=len;i++) {
        b[i]+=a[i];
    }
}

END {
    for (i=1;i<=maxlen;i++) {
        printf("%s ", b[i]);
    }
    print ""
}

Output

1 2 3 4 5
1 2 3 4 5
1 2 3 4 5
3 6 9 12 15