start=as.Date(\"2013-09-02\")
x[1:140]<-start
for(i in 2:140){
x[i]<-x[i-1]+1 }
what i get is something as such:
[1] \"2013
The problem is R doesn't allow matrices to be populated with dates. Both "matrix"
and "Date"
are classes. The underlying representation of a Date object in R is just an integer. So when you create your matrix y
, it takes the underlying data from x
(which is an array of integers), adds a dimension attribute, and makes the class "matrix"
.
There's not any clean way around this problem. There are a few hacks you can use, though. For example, you could explicitly force y
to be of class "Date"
as well as "matrix"
with class(y)<-c("matrix","Date")
. y
would still print out as just a vector of dates, but you would be able to manipulate it using matrix cordinates:
> class(y)<-c("matrix","Date")
> head(y)
[1] "2013-09-02" "2013-09-09" "2013-09-16" "2013-09-23" "2013-09-30"
[6] "2013-10-07" "2013-09-03" "2013-09-10" "2013-09-17" "2013-09-24"
[11] "2013-10-01" "2013-10-08" "2013-09-04" "2013-09-11" "2013-09-18"
[16] "2013-09-25" "2013-10-02" "2013-10-09" "2013-09-05" "2013-09-12"
[21] "2013-09-19" "2013-09-26" "2013-10-03" "2013-10-10" "2013-09-06"
[26] "2013-09-13" "2013-09-20" "2013-09-27" "2013-10-04" "2013-10-11"
[31] "2013-09-07" "2013-09-14" "2013-09-21" "2013-09-28" "2013-10-05"
[36] "2013-10-12" "2013-09-08" "2013-09-15" "2013-09-22" "2013-09-29"
[41] "2013-10-06" "2013-10-13"
> y[1,]
[1] "2013-09-02" "2013-09-03" "2013-09-04" "2013-09-05" "2013-09-06"
[6] "2013-09-07" "2013-09-08"
> y[1,]<-y[1,]+1
> y[1,]
[1] "2013-09-03" "2013-09-04" "2013-09-05" "2013-09-06" "2013-09-07"
[6] "2013-09-08" "2013-09-09"
You could also use a data frame instead of a matrix:
> y<-data.frame(y)
> y<-data.frame(lapply(y,function(x) {class(x)<-"Date";x}))
> head(y)
X1 X2 X3 X4 X5 X6 X7
1 2013-09-02 2013-09-03 2013-09-04 2013-09-05 2013-09-06 2013-09-07 2013-09-08
2 2013-09-09 2013-09-10 2013-09-11 2013-09-12 2013-09-13 2013-09-14 2013-09-15
3 2013-09-16 2013-09-17 2013-09-18 2013-09-19 2013-09-20 2013-09-21 2013-09-22
4 2013-09-23 2013-09-24 2013-09-25 2013-09-26 2013-09-27 2013-09-28 2013-09-29
5 2013-09-30 2013-10-01 2013-10-02 2013-10-03 2013-10-04 2013-10-05 2013-10-06
6 2013-10-07 2013-10-08 2013-10-09 2013-10-10 2013-10-11 2013-10-12 2013-10-13
A third possiblity is to keep the elements in y
in character format, and then convert them to dates using as.Date
when you need them:
> y<-matrix(as.character(x),nrow=20,byrow=T)
> head(y)
[,1] [,2] [,3] [,4] [,5]
[1,] "2013-09-02" "2013-09-03" "2013-09-04" "2013-09-05" "2013-09-06"
[2,] "2013-09-09" "2013-09-10" "2013-09-11" "2013-09-12" "2013-09-13"
[3,] "2013-09-16" "2013-09-17" "2013-09-18" "2013-09-19" "2013-09-20"
[4,] "2013-09-23" "2013-09-24" "2013-09-25" "2013-09-26" "2013-09-27"
[5,] "2013-09-30" "2013-10-01" "2013-10-02" "2013-10-03" "2013-10-04"
[6,] "2013-10-07" "2013-10-08" "2013-10-09" "2013-10-10" "2013-10-11"
[,6] [,7]
[1,] "2013-09-07" "2013-09-08"
[2,] "2013-09-14" "2013-09-15"
[3,] "2013-09-21" "2013-09-22"
[4,] "2013-09-28" "2013-09-29"
[5,] "2013-10-05" "2013-10-06"
[6,] "2013-10-12" "2013-10-13"
> as.Date(y[1,])
[1] "2013-09-02" "2013-09-03" "2013-09-04" "2013-09-05" "2013-09-06"
[6] "2013-09-07" "2013-09-08"