Generate a Swift array of nonrepeating random numbers

Question

I\'d like to generate multiple different random numbers in Swift. Here is the procedure.

1. Set up an empty array
2. Generate a random number

3. Ch

Answer 1

If you use your method the problem is, that you will create a new random-number each time. So you possibly could have the same random-number 4 times and so your array will only have one element.

So, if you just want to have an array of numbers from within a specific range of numbers (for example 0-100), in a random order, you can first fill an array with numbers in 'normal' order. For example with for loop etc:

var min = 1
var max = 5
for var i = min; i<= max; i++ {
    temp.append(i)
}

After that, you can use a shuffle method to shuffle all elements of the array with the shuffle method from this answer:

func shuffle(var list: C) -> C {
    let count = countElements(list)
    for i in 0..<(count - 1) {
        let j = Int(arc4random_uniform(UInt32(count - i))) + i
        swap(&list[i], &list[j])
    }
    return list
}

Ater that you can do something like that:

shuffle(temp)        // e.g., [3, 1, 2, 4, 5]