Regular expression for matching non-whitespace in Python

Question

I want to use re.search to extract the first set of non-whitespace characters. I have the following pseudoscript that recreates my problem:

#!/usr/b         


        

Answer 1

\s matches a whitespace character.

\S matches a non-whitespace character.

[...] matches a character in the set ....

[^...] matches a character not in the set ....

[^\S] matches a character that is not a non-whitespace character, i.e. it matches a whitespace character.