Regex for getting all digits in a string after a character

Question

I am trying to parse the following string and return all digits after the last square bracket:

C9: Title of object (foo, bar) [ch1, CH12,c03,4]

Answer 1

You can rather find all digits in the substring after the last [ bracket:

>>> s = 'C9: Title of object (fo[ 123o, bar) [ch1, CH12,c03,4]'
>>> # Get substring after the last '['.
>>> target_string = s.rsplit('[', 1)[1]
>>>
>>> re.findall(r'\d+', target_string)
['1', '12', '03', '4']

If you can't use split, then this one would work with look-ahead assertion:

>>> s = 'C9: Title of object (fo[ 123o, bar) [ch1, CH12,c03,4]'
>>> re.findall(r'\d+(?=[^[]+$)', s)
['1', '12', '03', '4']

This finds all digits, which are followed by only non-[ characters till the end.