nested functions in php throws an exception when the outer is called more than once

Question

lest assume that i have the following

function a(){
  function b(){}
}
a(); //pass
a(); //error

why in the second call an exception is thr

Answer 1

Declaring a function within another function like that would be considered bad practice in php. If you really need a function inside a() you should create a closure.

function a() {
  $b = function() {

  };
}