Can lapply pass (to a function) values stored in a vector, successively

Question

I need lapply to pass (to a function) values stored in a vector, successively.

values <- c(10,11,13,10)
lapply(foo,function(x) peakabif(x,npeaks=values))
         


        

Answer 1

There are a couple of ways to handle this. You could try a straight indexing vector approach.

lapply(1:length(foo), function(i) peakabif(foo[i], npeaks=values[i]))

(and someone already beat me to the mapply version...)