C++ function overloading resolution involving pass-by-value, reference and constant reference [duplicate]

Answer 1

You cannot overload:

void f(int x) {}
void f(const int& x) {}

Given those, the compiler won't be able to disambiguate the following call:

f(10);

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You cannot overload:

void f(int x) {}
void f(int& x) {}

Given those, the compiler won't be able to disambiguate the following call:

int i = 0;
f(i);

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You can overload:

void f(int& x) {}
void f(int const& x) {}

Given those, you can use:

int i = 0;
f(i);    // Resolves to f(int&)
f(10);   // Resolves to f(int const&)