Printing “array” from .bss in gdb

Question

my nasm x86 assembly code contains the following:

; The code should mimic the following C-code:
; int a[10];
; for (int i = 0; i < 10; i++){
;    a[i] = i         


        

Answer 1

; The code should mimic the following C-code:

In addition to wrong boundary noted by Jester, you also have the wrong initialization: your code is equivalent to:

 for (int i = 0; i < 10; i++) {
   a[i] = i + 1;  // different from stated goal of "a[i] = i;"
 }

However, how do i print array?

This is no different from printing array in C, when the source is compiled without debug info:

(gdb) p array
$1 = 0

(gdb) p {int[10]}&array
$2 = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

print array + X unfortunately is an arithmetical operation

You can then use:

(gdb) p $2[4]
$3 = 4