extracting a string between two quotes in bash

Question

I have example string like Test \"checkin_resumestorevisit - Online_V2.mt\" Run

and i want to extract the text between the two quotes in bash. I tried

Answer 1

Other weird ideas to not let @arton-dorneles alone :^)

But my favourite is @charles-duffy answer.

[[ "$SUBSTRING" =~ \"(.*)\" ]] && SUBSTRING="${BASH_REMATCH[1]}"

IFS=\" read -r _ SUBSTRING _ <<<"$SUBSTRING"

# bonus, match either ' or " by pair
SUBSTRING=$(echo "$SUBSTRING" | sed -r "s/.*?([\"'])(.*)\1.*/\2/")

Note that bash create a temporary file for "here string" (<<<) as it does for here documents.

Edit

It took me way too long to fully understand Charles Duffy critics; for readers, this could be when:

SUBSTRING='*"inside text" outside text'

In this scenario, the following would be unsafe because the star would be expanded, listing files and moving the desired result index:

IFS=\" eval '_=($SUBSTRING);SUBSTRING="${_[1]}"'

IFS=\" read -ra _ <<<"$SUBSTRING";SUBSTRING=${_[1]}