Method oveloading - Object vs Object vararg

Question

See the code below:

// 1st method
private static void method(Object o){
    System.out.println(\"object method\");
}
// 2nd method
private static void method         


        

Answer 1

Because Object... is essentially Object[] and since null is a valid Object[], it will match to the most specific one.

If you had 3 methods with first having Object parameter, the second having SubClass param and the last having SubSubClass param, the last one would be chosen.

Whereas if you add a method with a String parameter to your original code, you will get a compile time error, since there is no longer a single most specific match for null.