get a folder path from the explorer menu to a powershell variable

Question

is it possible to open a explorer window from powershell and store the path selected in the explorer, to a variable?

to open explorer window from powershell

Answer 1

The above did not work for me. Running Windows 7 with Powershell Version 2. I did find the following, which did allow the pop-up and selection:

    Function Select-FolderDialog
    {
         param([string]$Description="Select Folder",[string]$RootFolder="Desktop")

     [System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms") Out-Null     

     $objForm = New-Object System.Windows.Forms.FolderBrowserDialog
     $objForm.Rootfolder = $RootFolder
     $objForm.Description = $Description
     $Show = $objForm.ShowDialog()
     If ($Show -eq "OK")
     {
         Return $objForm.SelectedPath
     }
     Else
     {
        Write-Error "Operation cancelled by user."
     }
    }

Just in case others have the same issues.