How to schedule a Cron job to run 4th week of the year

Question

I work on an application that uses native Unix CRON tab for scheduling jobs. the description of parameters are as follows :

Minute, Hour, Da_of_Week(1-7, 1=         


        

Answer 1

You have to put a condition in your crontab to do that. Your cron will look something like this,

 0 20 1-7 1 *  root [ `date +%a` == "Mon" ] && /run/some/script

cron 0 20 1-7 1 * runs at 8pm everyday from 1st to 7th in the month of January.

Following checks that the day is Monday before executing your script.

 [ `date +%a` == "Mon" ]

With this, script will run on the 7th January 2019, which is within the first week of the year.

$ cal 01 2019
    January 2019    
Su Mo Tu We Th Fr Sa
       1  2  3  4  5
 6  7  8  9 10 11 12
13 14 15 16 17 18 19
20 21 22 23 24 25 26
27 28 29 30 31