Implementing Disjoint Set System In Python

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无人及你
无人及你 2021-01-19 03:47

What I have so far is largely based off page 571 of \"Introduction To Algorithms\" by Cormen et al.

I have a Node class in python that represents a set:



        
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  •  生来不讨喜
    2021-01-19 04:09

    The Wikipedia page provides pseudocode for the basic operations on disjoint-set data structure. Here's a direct port to Python (employs path compression and union by rank):

    class Node:
        """Represents an element of a set."""
        def __init__(self, id):
            self.id = id
            self.parent = self
            self.rank = 0
            self.size = 1
    
        def __repr__(self):
            return 'Node({!r})'.format(self.id)
    
    
    def Find(x):
        """Returns the representative object of the set containing x."""
        if x.parent is not x:
            x.parent = Find(x.parent)
        return x.parent
    
    
    def Union(x, y):
        """Combines the sets x and y belong to."""
        xroot = Find(x)
        yroot = Find(y)
    
        # x and y are already in the same set
        if xroot is yroot:
            return
    
        # x and y are not in same set, so we merge them
        if xroot.rank < yroot.rank:
            xroot, yroot = yroot, xroot  # swap xroot and yroot
    
        # merge yroot into xroot
        yroot.parent = xroot
        xroot.size += yroot.size
        if xroot.rank == yroot.rank:
            xroot.rank = xroot.rank + 1
    

    Demo:

    >>> a, b, c = map(Node, 'abc')
    >>> Find(a), Find(b), Find(c)
    (Node('a'), Node('b'), Node('c'))
    >>> Find(a).size
    1
    >>> Union(a, b)
    >>> Union(b, c)
    >>> Find(a), Find(b), Find(c)
    (Node('a'), Node('a'), Node('a'))
    >>> Find(a).size
    3
    

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