I\'d like to print list item with the index of item such as
0: [(\'idx\', 10), (\'degree\', 0)]
1: [(\'idx\', 20), (\'degree\', 0)]
Based o
I would do it like this.
def funcA():
a = []
a.append(Node(10, 0))
a.append(Node(20, 0))
for i in range(0, len(a)):
message = '%s:%s' % (i, a[i].items())
logging.debug(message)
Which produces this as output:
DEBUG:root:0:[('idx', 10), ('degree', 0)]
DEBUG:root:1:[('idx', 20), ('degree', 0)]
You could also use join:
message = ':'.join([str(i), str(a[i].items())])
Or format:
message = '{0}:{1}'.format(str(i), a[i].items())
Whatever is the most clear to you.