I am having problems parsing time strings in Java that are in the format of 2013-01-09 09:15:03.000000
. In my data, the last three digits are always 0 (meaning
I should like to contribute the modern answer. Use java.time
, the modern Java date and time API. One option, you may use a formatter:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss.SSSSSS");
LocalDateTime dateTime = LocalDateTime.parse(timeString, formatter);
System.out.println(dateTime);
When using the string from your question, "2013-01-09 09:15:02.500000"
, this printed:
2013-01-09T09:15:02.500
If you want the value printed with six decimals on the seconds even when the last three decimals are 0, use the same formatter to format the time back into a string:
System.out.println(dateTime.format(formatter));
The other option, you may exploit the fact that your string resembles the ISO 8601 format, the format that the modern classes parse as their default, that is, without any explicit formatter. Only ISO 8601 has a T
to denote the start of the time part, but we can fix that easily:
LocalDateTime dateTime = LocalDateTime.parse(timeString.replace(' ', 'T'));
It gives the same result, 2013-01-09T09:15:02.500
. It’s shorter, but also more tricky.
The classes Date
and Timestamp
are long outdated, and SimpleDateFormat
in particular has proven troublesome. Its surprising behaviour in your situation is just one little story out of very many. The modern API is generally so much nicer to work with.
While the format pattern strings used by SimpleDateFormat
and DateTimeFormatter
are similar, there are differences. One is that SimpleDateFormat
understands uppercase S
as milliseconds no matter of there are one or nine of them, whereas to DateTimeFormatter
they mean fraction of second. Your SimpleDateFormat
furthermore grabbed all six digits after the decimal point, ignoring the fact that you had typed only three S
, so there were no zeroes left to match the '000'
(by the way, the apostrophes are not necessary, only letters need them).
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