How can I create a PNG image file from a list of pixel values in Python?

前端 未结 2 1322
野趣味
野趣味 2021-01-19 00:58

I can generate a list of pixel values from an existing image file using a procedure like the following:

from PIL import Image
image = Image.open(\"test.png\"         


        
2条回答
  •  执笔经年
    2021-01-19 01:49

    Quick fix

    First, you need to have your pixel tuples in a single un-nested list:

    pixels_out = []
    for row in pixels:
        for tup in row:
            pixels_out.append(tup)
    

    Next, make a new image object, using properties of the input image, and put the data into it:

    image_out = Image.new(image.mode,image.size)
    image_out.putdata(pixels_out)
    

    Finally, save it:

    image_out.save('test_out.png')
    

    Fundamental issue

    Your list comprehension generates a list of lists, the latter being generated by the slicing (i*width:(i+1)*width). Your comprehension can be much easier: pixels = [pixel for pixel in pixels]. Obviously this outputs the same list, pixels, but you can use the idea to perform an operation on the pixels, e.g. pixels = [operation(pixel) for pixel in pixels].

    Really, you overthought it. You don't have to manage the image dimensions. Getting the pixels in a list, and then putting them into an equal-sized image with putdata keeps the in order because they are linearized the same way by PIL.

    In short, this is what your original snippet should have been:

    from PIL import Image
    image = Image.open("test.png")
    image_out = Image.new(image.mode,image.size)
    
    pixels = list(image.getdata())
    image_out.putdata(pixels)
    image_out.save('test_out.png')
    

提交回复
热议问题