python: group elements of a tuple having the same first element

Question

i have a tuple like this

[
(379146591, \'it\', 55, 1, 1, \'NON ENTRARE\', \'NonEntrate\', 55, 1), 
(4746004, \'it\', 28, 2, 2, \'NON ENTRARE\', \'NonEntrate\         


        

Answer 1

u can use collection.defaultdict:

data = [
    (379146591, 'it', 55, 1, 1, 'NON ENTRARE', 'NonEntrate', 55, 1), 
    (4746004, 'it', 28, 2, 2, 'NON ENTRARE', 'NonEntrate', 26, 2), 
    (4746004, 'it', 28, 2, 2, 'TheBestTroll Group', 'TheBestTrollGroup', 2, 3)
    ]
from collections import defaultdict
a = defaultdict(list)
a = defaultdict(list)


from collections import defaultdict
a = defaultdict(list)

for d in data:
    a[d[0]].append(d[1:])

for k,v in a.items():
    a[k] = tuple(a[k])

print(dict(a))