Create a JPA Criteria fully dynamically

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闹比i
闹比i 2021-01-18 21:11

Usually I\'m a Hibernate user and for my new project we use JPA 2.0.

My DAO receives a Container with a generic.

public class Container {
          


        
1条回答
  •  逝去的感伤
    2021-01-18 21:26

    As long as your T is Comparable (it's required for greaterThan), you should be able to do something like the following:

    public class Container> { 
        ...
        public  Predicate toPredicate(CriteriaBuilder cb, Root root) {
            ...
            if (">".equals(operation) {
                return cb.greaterThan(root.get(fieldId), value);
            } 
            ...
        }
        ...
    }
    

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