How would one go about launching the browser from an activity without specifying a url. I would like to open the browser so the user can continue browsing without changing t
In case it (the ComponentName("com.android.browser", "com.android.browser.BrowserActivity")) changes in the future, you may try something like the following code:
public static ComponentName getDefaultBrowserComponent(Context context) {
Intent i = new Intent()
.setAction(Intent.ACTION_VIEW)
.setData(new Uri.Builder()
.scheme("http")
.authority("x.y.z")
.appendQueryParameter("q", "x")
.build()
);
PackageManager pm = context.getPackageManager();
ResolveInfo default_ri = pm.resolveActivity(i, 0); // may be a chooser
ResolveInfo browser_ri = null;
List rList = pm.queryIntentActivities(i, 0);
for (ResolveInfo ri : rList) {
if (ri.activityInfo.packageName.equals(default_ri.activityInfo.packageName)
&& ri.activityInfo.name.equals(default_ri.activityInfo.name)
) {
return ri2cn(default_ri);
} else if ("com.android.browser".equals(ri.activityInfo.packageName)) {
browser_ri = ri;
}
}
if (browser_ri != null) {
return ri2cn(browser_ri);
} else if (rList.size() > 0) {
return ri2cn(rList.get(0));
} else if (default_ri == null) {
return null;
} else {
return ri2cn(default_ri);
}
}
private static ComponentName ri2cn(ResolveInfo ri) {
return new ComponentName(ri.activityInfo.packageName, ri.activityInfo.name);
}
Basically, here I construct an intent to view a dummy http page, get the list of activities that may handle the intent, compare it to the default handler returned by resolveActivity() and return something. I do not need to check if there's a launcher MAIN action (my code uses the VIEW action), but you probably should.