How to get all indexes of a pattern in a string?

Question

I want something like this:

\"abcdab\".search(/a/g) //return [0,4]

Is it possible?

Answer 1

Another non-regex solution:

function indexesOf(str, word) {
   const split = str.split(word)
   let pointer = 0
   let indexes = []

   for(let part of split) {
      pointer += part.length
      indexes.push(pointer)
      pointer += word.length
   }

   indexes.pop()

   return indexes
}

console.log(indexesOf('Testing JavaScript, JavaScript is the Best, JavaScript is Ultimate', 'JavaScript'))