Integer to byte casting in Java

Question

In Java we can do

byte b = 5;    

But why can\'t we pass same argument to a function which accepts byte

myObj         


        

Answer 1

Hard-coded initializer values are somewhat special in Java - they're assumed to have a coercion to the type of the variable you're initializing. Essentially, that first bit of code effectively looks like this:

byte b = (byte) 5;

If you did this...

myObject.testByte((byte) 5);

...you wouldn't get that error, but if you don't do that, then the 5 is created by default as an int, and not automatically coerced.