Do objects of built-in types have special static initialisation order precedence?

Question

I\'d have expected the following code to yield a segmentation fault (or otherwise UB):

struct T {
   T();
};

T t;
char const* str = \"Test string\";

T::T()         


        

Answer 1

char const* str = "Test string";

is done by the compiler/linker, so it exists in its "initialized state" before the program even starts to run.